Question #1437
Two charged objects separated by 21 cm have a repulsive force of 0.02 N. If the distance in charged to 7 cm, what will be be the resulting repulsive force?
Expert's answer
The repulsive force is
F1 = kq1q2/R12
kq1q2 = F1R12
Then
F2 =k q1q2/R22 = F1R12/R22 = 0.02*212/72 = 0.18 N.
F1 = kq1q2/R12
kq1q2 = F1R12
Then
F2 =k q1q2/R22 = F1R12/R22 = 0.02*212/72 = 0.18 N.
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