Two charged objects separated by 21 cm have a repulsive force of 0.02 N. If the distance in charged to 7 cm, what will be be the resulting repulsive force?
1
Expert's answer
2011-01-31T12:25:59-0500
The repulsive force is F1 = kq1q2/R12
kq1q2 = F1R12 Then F2 =k q1q2/R22 = F1R12/R22 = 0.02*212/72 = 0.18 N.
Numbers and figures are an essential part of our world, necessary for almost everything we do every day. As important…
APPROVED BY CLIENTS
"assignmentexpert.com" is professional group of people in Math subjects! They did assignments in very high level of mathematical modelling in the best quality. Thanks a lot
Comments
Leave a comment