Answer to Question #142513 in Electricity and Magnetism for sridhar

Question

The ratio of the magnetic field inside a solenoid at an axial point well inside and at an axial end point is

Ans 2

Answer 1

if magnetic permeability =$\mu$ , current flowing =I ,Number of turns per unit length =n

then magnetic field inside solenoid = $\mu \times n\times I$ .............(1)

Magnetic field near the Axial End point = $\frac{\mu \times n \times I}{2}$ ............(2)

Hence field ratio = $\frac{equation 1}{equation 2} = 2$

Answer =2