Question

How many electrons must pass through a circuit to account for 443 coulombs of charge?

Answer 1

The whole charge of N electrons is $Q = 443C$, the charge of one electron is known: $e = 1.6 \times 10^{-19}C$. Hence, the number of electrons can be calculated as:

$$N = \frac{Q}{e} = \frac{443C}{1.6 \times 10^{-19}C} = 27.7 \times 10^{20}$$