"E = E_0 \\sin (\\omega t-kz)"
In EM wave E and H are connected as
"\\sqrt{\\epsilon \\epsilon_0}\\, E = \\sqrt{\\mu\\mu_0}\\, H"
So, "H = \\sqrt{\\frac{\\epsilon \\epsilon_0}{\\mu\\mu_0}}\\, E = \\sqrt{\\frac{\\epsilon \\epsilon_0}{\\mu\\mu_0}}\\, E_0 \\sin (\\omega t - kz)"
"D = \\epsilon \\epsilon_0E, \\; B = \\mu \\mu_0 H", therefore
"D = \\epsilon \\epsilon_0 E_0 \\sin (\\omega t-kz)" and
"B = \\sqrt{\\epsilon \\epsilon_0 \\mu \\mu_0} \\, E_0 \\sin (\\omega t-kz)".
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