Question #137632
If the expression for the field quantity E in free space is given by: E= E_0 Sin (ωt-kz)a_x,where E_o,ω&k are constants.Find the remaining three field quantities. (i.e. D, B & H)
1
Expert's answer
2020-10-12T07:47:21-0400

E=E0sin(ωtkz)E = E_0 \sin (\omega t-kz)

In EM wave E and H are connected as

ϵϵ0E=μμ0H\sqrt{\epsilon \epsilon_0}\, E = \sqrt{\mu\mu_0}\, H

So, H=ϵϵ0μμ0E=ϵϵ0μμ0E0sin(ωtkz)H = \sqrt{\frac{\epsilon \epsilon_0}{\mu\mu_0}}\, E = \sqrt{\frac{\epsilon \epsilon_0}{\mu\mu_0}}\, E_0 \sin (\omega t - kz)

D=ϵϵ0E,  B=μμ0HD = \epsilon \epsilon_0E, \; B = \mu \mu_0 H, therefore

D=ϵϵ0E0sin(ωtkz)D = \epsilon \epsilon_0 E_0 \sin (\omega t-kz) and

B=ϵϵ0μμ0E0sin(ωtkz)B = \sqrt{\epsilon \epsilon_0 \mu \mu_0} \, E_0 \sin (\omega t-kz).


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