E=E0sin(ωt−kz)E = E_0 \sin (\omega t-kz)E=E0sin(ωt−kz)
In EM wave E and H are connected as
ϵϵ0 E=μμ0 H\sqrt{\epsilon \epsilon_0}\, E = \sqrt{\mu\mu_0}\, Hϵϵ0E=μμ0H
So, H=ϵϵ0μμ0 E=ϵϵ0μμ0 E0sin(ωt−kz)H = \sqrt{\frac{\epsilon \epsilon_0}{\mu\mu_0}}\, E = \sqrt{\frac{\epsilon \epsilon_0}{\mu\mu_0}}\, E_0 \sin (\omega t - kz)H=μμ0ϵϵ0E=μμ0ϵϵ0E0sin(ωt−kz)
D=ϵϵ0E, B=μμ0HD = \epsilon \epsilon_0E, \; B = \mu \mu_0 HD=ϵϵ0E,B=μμ0H, therefore
D=ϵϵ0E0sin(ωt−kz)D = \epsilon \epsilon_0 E_0 \sin (\omega t-kz)D=ϵϵ0E0sin(ωt−kz) and
B=ϵϵ0μμ0 E0sin(ωt−kz)B = \sqrt{\epsilon \epsilon_0 \mu \mu_0} \, E_0 \sin (\omega t-kz)B=ϵϵ0μμ0E0sin(ωt−kz).
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