Solution
Given data
Flux "(\\Phi) =0.013" Webers
Diameter=12cm
Radius(r) =6cm=0.06m
Area(A) ="\\pi r^2 =3.14\\times0.06\\times0.06"
=0.0113 "m^2"
Flux density can be expressed as
"B=\\frac{\\Phi}{A}=\\frac{0.013}{0.0113}=1.15Tesla"
Therefore flux density is 1.15 T.
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