Solution
Given data
Flux (Φ)=0.013(\Phi) =0.013(Φ)=0.013 Webers
Diameter=12cm
Radius(r) =6cm=0.06m
Area(A) =πr2=3.14×0.06×0.06\pi r^2 =3.14\times0.06\times0.06πr2=3.14×0.06×0.06
=0.0113 m2m^2m2
Flux density can be expressed as
B=ΦA=0.0130.0113=1.15TeslaB=\frac{\Phi}{A}=\frac{0.013}{0.0113}=1.15TeslaB=AΦ=0.01130.013=1.15Tesla
Therefore flux density is 1.15 T.
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