Question

a package is drop from the drone which is raising with velocity 0.5m/sec.find the distance between package and drone after 2.5sec?

Answer 1

When a package is dropped from drone its initial velocity will be

$u_p = -0.5 \;m/sec$

Taking upward vertical direction as negative.

$S_2 = u_pt + ½ at^2$

$S_2 = -0.5\times 2.5 + ½ \times 9.8 \times (2.5)^2$

$S_2 = -1.25 + 30.625 = 29.375\; m$

$S_1 = u_dt + ½at^2$

a – acceleration of the drone (a = 0)

$S_1 = u_dt$

$S_1 = -0.5 \times 2.5 = -1.25 \;m$

Negative sign indicates upward direction of displacement.

$S = S_1 + S_2$

$S = 1.25 + 29.375 = 30.625\; m$

Answer: 30.625 m