Question #134307
Point charges are placed at the vertices of a square of side L as shown in figure. what should be sign of charge q and magnitude of the ratio |q/Q| so that

(a) net force on each Q is zero?

(b) net force on each q is zero?

(c) Is it possible that the entire system could be in electrostatic equilibrium?
1
Expert's answer
2020-09-21T09:42:17-0400

(a)


kqQa2222kQQ(a2)2=0qQ=122k\frac{qQ}{a^2}\cdot \frac{\sqrt2}{2}\cdot2-k\frac{QQ}{({a\sqrt{2}})^2}=0\to \frac{q}{Q}=\frac{1}{2\sqrt2}


the sign of qq should be the negative of Q.Q.


(b)


kqQa2222kqq(a2)2=0qQ=22k\frac{qQ}{a^2}\cdot \frac{\sqrt2}{2}\cdot2-k\frac{qq}{({a\sqrt{2}})^2}=0\to \frac{q}{Q}=2\sqrt2


the sign of qq should be the negative of Q.Q.


(c)


The entire system cannot be in equilibrium since both conditions i.e.


q=Q22q=-\frac{Q}{2\sqrt2}


and


Q=q22Q=-\frac{q}{2\sqrt2}


cannot be satisfied together.







Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS