Answer to Question #134071 in Electricity and Magnetism for Rohit

Question

A charge of 5C charge is placed at origin and a charge of 3C find at 2meter distance find force due to charge on each other

Answer 1

We can find the force between the two charges from the Coulomb's law:

$$F = \dfrac{kq_1q_2}{r^2},$$

here, $F$ is the force between the two charges, $k = 9 \cdot 10^9 \ \dfrac{N \cdot m^2}{C^2}$ is Coulomb's constant, $q_1 = 5 \ C$ is the magnitude of the first charge, $q_2 = 3 \ C$ is the magnitude of the second charge,

$r = 2 \ m$ is the distance between the charges.

Then, we can calculate the force between the two charges:

$$F = \dfrac{9 \cdot 10^9 \ \dfrac{N \cdot m^2}{C^2} \cdot 5 \ C \cdot 3 \ C}{(2 \ m)^2} = 33.75 \cdot 10^9 \ N.$$

Answer:

$F = 33.75 \cdot 10^9 \ N.$