Answer to Question #134071 in Electricity and Magnetism for Rohit

Question #134071
A charge of 5C charge is placed at origin and a charge of 3C find at 2meter distance find force due to charge on each other
1
Expert's answer
2020-09-22T17:08:46-0400

We can find the force between the two charges from the Coulomb's law:


F=kq1q2r2,F = \dfrac{kq_1q_2}{r^2},

here, FF is the force between the two charges, k=9109 Nm2C2k = 9 \cdot 10^9 \ \dfrac{N \cdot m^2}{C^2} is Coulomb's constant, q1=5 Cq_1 = 5 \ C is the magnitude of the first charge, q2=3 Cq_2 = 3 \ C is the magnitude of the second charge,

r=2 mr = 2 \ m is the distance between the charges.

Then, we can calculate the force between the two charges:


F=9109 Nm2C25 C3 C(2 m)2=33.75109 N.F = \dfrac{9 \cdot 10^9 \ \dfrac{N \cdot m^2}{C^2} \cdot 5 \ C \cdot 3 \ C}{(2 \ m)^2} = 33.75 \cdot 10^9 \ N.

Answer:

F=33.75109 N.F = 33.75 \cdot 10^9 \ N.


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