Let the charge on the sphere be Q and the radius of the sphere be R.
We may apply the Gauss's law (see https://en.wikipedia.org/wiki/Gauss%27s_law) to the sphere. The total flux "\\Phi" through the surface of the sphere ("4\\pi R^2" ) is proportional to the total charge inside the sphere:
"\\Phi = E \\cdot S = E \\cdot 4\\pi R^2 = \\dfrac{Q}{\\varepsilon_0}" . Therefore, the field of the sphere will be
"E = \\dfrac{Q}{4\\pi\\varepsilon_0 R^2}," where "\\varepsilon_0" is the vacuum permittivity (ε0 = 8.8541878128(13)×10−12 F⋅m−1).
More detailed derivation can be found in farside.ph.utexas.edu/teaching/302l/lectures/node25.html for the negative charge.
Comments
Leave a comment