If a circuit has 50 Hz frequency and its peak value is 20V. Calculate the sinusoidal voltage. Also calculate the time for one cycle and draw the corresponding voltage versus time graph.
Given data
frequency(f)=50 Hz
peak value of voltage(V0)=20 Volt
Angular frequency of sinusoidal voltage wave
"\\omega =2 \\pi f"
"\\implies \\omega=2\\pi\\times50=100\\pi" rad/sec
standard sinusoidal form of voltage is given by
"V=V_{0}\\sin\\omega t"
putting value of V0 and "\\omega" then
"{V=20\\sin100\\pi t}"
time period for one cycle is given by
"T=\\frac{1}{f}= \\frac{2\\pi}{\\omega}"
Now "T=\\frac{1}{50}=0.02 sec"
therefore sinusoidal voltage form is "V=V_{0}\\sin100\\pi t" and time period for one cycle "T=0.02 sec".
"\\implies" voltage versus time graph is below
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