As per the question,
Number of turns (n)=20
Area (A)=2.0×10−2m2
Magnetic field (B)=0.4T
Rotational frequency (f)=50Hz
(i) The flux linkage (ϕ)=nBA
Now substituting values in the above,
⇒ϕ=20×2.0×10−2×0.4 Tm2
=16.0×10−2Tm2
(ii) Emf produced by the generator e=nBAω
e=nBA×2πf
Now, substituting the values,
⇒e=20×0.4×2.0×10−2×2×3.14×50Tm2rad/sec
⇒e=50.24V
Comments
Thank you so much!