As per the given question,
Magnetic field (B)=4.252T
Maximum current (i)=1000A
μo=1.25664×10−6T⋅m/A.
Interior magnetic field of the solenoid (B)=μonI
Number of binding per meter (N)=μoIB
Now, substituting the values in the above,
N=1.25664×10−6×1000A.T⋅m/A.4.25T
⇒N=3400turn/meter
Comments
Leave a comment