Let ddd be the distance from the object to the mirror, fff be the distance from image to the mirror and FFF be the focal length. The relation between these parameters is (for the virtual image)
1d−1f=1F.\dfrac1d -\dfrac1f = \dfrac1F.d1−f1=F1. So 1d=1f+1F=110+115=16.\dfrac1d = \dfrac1f + \dfrac1F = \dfrac{1}{10} + \dfrac{1}{15} = \dfrac16.d1=f1+F1=101+151=61. Therefore, d=6 cm.d=6\,\mathrm{cm}.d=6cm.
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