Answer to Question #122259 in Electricity and Magnetism for Dheeraj

Question

In a dielectric material having ε = 12 the displacement current is 25 times greater than
the conduction current at 100 MHz . The conductivity of the dielectric is

Answer 1

Assume that we have a conduction current $J_c$, displacement current $J_d$.

The conductivity will be

$$\sigma=\omega\epsilon\epsilon_0\frac{J_c}{J_d},\\\sigma=2\pi\cdot10^8\cdot12\cdot8.85\cdot10^{-12}\cdot\frac{1}{25}=0.00267\text{ S/m}.$$