Question

The voltage of the X Ray tube is 80kv calculate the maximum energy and the shortest wavelength of the Xray photon

Answer 1

Shortest wavelength $=\frac{hc}{eV}=\frac{6.63\times10^{-34}\times3\times10^8}{1.6\times10^{-19}\times80\times10^3}=0.155\times10^{-10}m=0.155A^o$

maximum energy = $\frac{hc}{\lambda_{min}}=\frac{6.63\times10^{-34}\times3\times10^8}{0.155\times10^{-10}}=1.28\times10^{-14}J$