As per the given question,
Operating voltage = 6V,
Power = 48W
Supply voltage = 240V AC
Ns=100
We know that "(\\frac{E_1}{E_2})=(\\frac{N_1}{N_2})"
"\\Rightarrow N_2=\\frac{E_2\\times N_1}{E_1}"
"\\Rightarrow N_2=\\frac{240\\times 100}{6}=4000"
Hence, total number of turns in the coil is 4000.
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