As per the given question,
Operating voltage = 6V,
Power = 48W
Supply voltage = 240V AC
Ns=100
We know that (E1E2)=(N1N2)(\frac{E_1}{E_2})=(\frac{N_1}{N_2})(E2E1)=(N2N1)
⇒N2=E2×N1E1\Rightarrow N_2=\frac{E_2\times N_1}{E_1}⇒N2=E1E2×N1
⇒N2=240×1006=4000\Rightarrow N_2=\frac{240\times 100}{6}=4000⇒N2=6240×100=4000
Hence, total number of turns in the coil is 4000.
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