Let the charge is q,
so electric potential at the distance r is
"V=\\frac{q}{4\\pi \\epsilon_o r}"
if r is infinite then potential "(V)=\\frac{q}{4\\pi \\infty}=0"
Now, if"( r)=1.00mm=1.0\\times 10^{-3}m"
"V=\\frac{q}{4\\pi \\epsilon_o\\times 1.0\\times 10^{-3}m}"
"=\\frac{q\\times 10^{3}}{4\\pi \\epsilon_o}"
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