Given data
Charge is q=−5.00∗10−6Cq=-5.00*10^{-6} Cq=−5.00∗10−6C
The electric potential at a point P which is 2.00 m from a point charge of -5.00µC is
V=kqr=(9∗109)(−5.00∗10−6)2.00V=\frac{kq}{r}=\frac{(9*10^9)(-5.00*10^{-6})}{2.00 }V=rkq=2.00(9∗109)(−5.00∗10−6)
=−2.25∗104V=-2.25*10^4 V=−2.25∗104V
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