Answer to Question #119746 in Electricity and Magnetism for Lindon

Question #119746
A charge which has a magnitude of 18 nanoCoulomb produces an electric field. At a distance r the strength of Electric field is equal to . How far is the source charge from the charge?
1
Expert's answer
2020-06-03T12:04:00-0400

The strength of electric field EE produced by the charge qq at a distance rr is given by the equation:


E=14πε0qr2E = \dfrac{1}{4\pi\varepsilon_0}\dfrac{q}{r^2}

where ε0=8.851012F/m\varepsilon_0 = 8.85\cdot 10^{-12} F/m is the permittivity of free space.

Thus, for the given charge and strength of electric field the distance will be:


r=q4πε0Er = \sqrt{\dfrac{q}{4\pi\varepsilon_0E}}

Answer. r=q4πε0E.r = \sqrt{\dfrac{q}{4\pi\varepsilon_0E}}.


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