Question

A wire carries a current of 10A in a direction 30º to a uniform magnetic field of
0.30 T. Find the force on 5.0 m of the wire.

Answer 1

Given data

Current $I=10 A$

Magnetic field is $B=0.30 T$

Length of wire is $L=5.0 m$

The magnetic force on the wire is

$F=BILsin 30^o=(0.30)(10)(5.0)sin30^o=7.50 N$