Given data
rms value of electric field is "E_{rms}=3550 N\/C"
The maximum value of electric field is
"E_{max}=\\sqrt{2}E_{rms}=\\sqrt{2}(3550 N\/C)=5020 N\/C"
The intensity of electromagnetic wave is
"I=\\frac{{E_{max}}^2}{2\\mu_{0}c}=\\frac{{5020}^2}{2(4\\pi*10^{-7})(3*10^8)}=3.34*10^4 W\/m^2"
The power delivered to the leg is
"P=IA=I\\pi r^2=(3.34*10^4)(\\pi(0.02 m)^2 =42 W"
Comments
Leave a comment