Answer to Question #116229 in Electricity and Magnetism for Enoch

Question #116229
A long straight wire carries a current 1.5A. an electron travels with a speed of 5*10^6cm/sec parallel to the wire 10cm from it and in the same direction as the current. What force does the magnetic field of the current exert on the moving electron
1
Expert's answer
2020-05-19T10:39:54-0400

First of all let's see the magnitude of magnetic field created by wire carrying current

B=μoI2πr=4π×104×1.52π×0.1=3×103TB=\frac{\mu_oI}{2\pi r}=\frac{4\pi\times10^{-4}\times1.5}{2\pi\times0.1}=3\times10^{-3}T


force due to magnetic field =q(v×B)=1.6×1019(5×106×3×103)=2.4×1015Nq(v\times B)=1.6\times10^{-19}(5\times10^6\times3\times10^{-3})=2.4\times10^{-15}N =


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment