First of all let's see the magnitude of magnetic field created by wire carrying current
B=μoI2πr=4π×10−4×1.52π×0.1=3×10−3TB=\frac{\mu_oI}{2\pi r}=\frac{4\pi\times10^{-4}\times1.5}{2\pi\times0.1}=3\times10^{-3}TB=2πrμoI=2π×0.14π×10−4×1.5=3×10−3T
force due to magnetic field =q(v×B)=1.6×10−19(5×106×3×10−3)=2.4×10−15Nq(v\times B)=1.6\times10^{-19}(5\times10^6\times3\times10^{-3})=2.4\times10^{-15}Nq(v×B)=1.6×10−19(5×106×3×10−3)=2.4×10−15N =
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