Question

A current 5A passes through a straight wire in a uniform magnitude field of a flux density of 2.0x10-3 T. Calculate the force per unit length exerted on the wire when it is inclined at 30° to the field.

Answer 1

given data :

$I = 5A$

$B = 2.0\times 10 -3 T = 20-3 =17 T = 17 \frac{Wb}{m^{2}}$

$\theta$ = 30$\degree$

Equation of Force  $F = IBL sin \theta$

Force per unit length $\frac{F}{L} = IB sin \theta$

$\frac{F}{L} = 5\times 17\times sin 30\degree$

$\frac{F}{L} = 42.5 \frac{N}{m}$