Question

Find the total capacitance for three capacitors connected in series, given their individual capacitances
are

Answer 1

Assume that we have three capacitors with corresponding capacitances $C_1,C_2, C_3$. Let us find the total (equivalent) capacitance $C$ of the series combination of our capacitors:

$$\frac{1}{C}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3},\\ \space\\ C=\frac{C_1C_2C_3}{C_1C_2+C_2C_3+C_1C_3}.$$