Question

the plates of a parallel plate capacitor,5.0x10^-3m apart are maintained at a potential difference of 5.0x10^4 calculate the magnitude of the i. electric field intensity between the plates ii. force on the electron.

Answer 1

Potential between plates is defined as $U=Ed$ , where $U$-potential between plates, $E$-electric field, $d$-distance between plates. Thus, $E=\dfrac{U}{d}=\dfrac{5\cdot 10^4}{5\cdot 10^{-3}}=10^{7} ~V/m$. Force on electron $F=qE\approx1.6\cdot10^{-19}\cdot10^7\approx1.6\cdot 10^{-12}$