Answer to Question #115274 in Electricity and Magnetism for Sara

Question

An ideal transformer is supplied with voltage 240 V. It is found that the potential difference of the secondary coil is 12 V and the current is 3 A. Find the current in the primary coil.

Answer 1

Ohm's low

V = I $\times$ R

Data Given

V₁ = 240 V

V₂ = 12 V

I₂ = 3A

I₁ = ?

we know that , relationship of voltage and current,

Voltage directly proportional to current,

$V \propto I$

$\frac{V_{1}} {V_{2}}=\frac{I_{1}} {I_{2}}$

$I_{1} =I_{2}\times\frac{V_{1}} {V_{2}}$

$I_{1} =3 \times\frac{240} {12}$

$I_{1} = 60 A$