As the diagram not given in the question,
but here resistance "(R)=8.0 \\Omega"
Current in the circuit "(i)=0.5A"
the potential of the battery
"V= iR"
"\\Rightarrow V = 8\\times 0.5 = 4V"
If all are connected in series then the current in all the resistance will be same.
Electrical power "(P)=VI"
"=4\\times 0.5 = 2watt"
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