Question #113322
In a mass spectrometer, a particle is ionized to include an additional proton. It is then accelerated to a velocity of 54000 m/s and allowed to enter a magnetic field of 10 T where it is deflected in a semi-circular path with a radius of 2 mm. What is the mass of the particle?
1
Expert's answer
2020-05-05T18:34:20-0400

Lorentz force acts on a charge moving in a magnetic field

F=qvBF=q \cdot v \cdot B

The Lorentz force plays the role of a centripetal force, so we can write

mqv2R=qvB\frac {m_q \cdot v^2}{R}=q \cdot v \cdot B

Where will we write

mq=qvBRv2=qBRv=1.610191021035.4104=5.9261026kgm_q=\frac{q \cdot v \cdot B \cdot R}{v^2}=\frac{q \cdot B \cdot R}{v}=\frac{1.6 \cdot 10^{-19} \cdot 10 \cdot 2 \cdot 10^{-3}}{5.4 \cdot 10^4}=5.926 \cdot 10^{-26}kg


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