Answer to Question #113322 in Electricity and Magnetism for sabrina

Question #113322
In a mass spectrometer, a particle is ionized to include an additional proton. It is then accelerated to a velocity of 54000 m/s and allowed to enter a magnetic field of 10 T where it is deflected in a semi-circular path with a radius of 2 mm. What is the mass of the particle?
1
Expert's answer
2020-05-05T18:34:20-0400

Lorentz force acts on a charge moving in a magnetic field

"F=q \\cdot v \\cdot B"

The Lorentz force plays the role of a centripetal force, so we can write

"\\frac {m_q \\cdot v^2}{R}=q \\cdot v \\cdot B"

Where will we write

"m_q=\\frac{q \\cdot v \\cdot B \\cdot R}{v^2}=\\frac{q \\cdot B \\cdot R}{v}=\\frac{1.6 \\cdot 10^{-19} \\cdot 10 \\cdot 2 \\cdot 10^{-3}}{5.4 \\cdot 10^4}=5.926 \\cdot 10^{-26}kg"


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