As T=2πlgT=2\pi\sqrt{\frac{l}{g}}T=2πgl
This is the time taken by the pendulum for one oscillation.
If temperature increases by 10°C10°C10°C , then new length of pendulum l′=l(1+α∆T)l'=l(1+\alpha∆T)l′=l(1+α∆T)
Length of the pendulum increases so
T′=2πl′gT'=2\pi\sqrt{\frac{l'}{g}}T′=2πgl′
As l′>l ⟹ T′>Tl'>l\implies T'>Tl′>l⟹T′>T
So the pendulum takes more time for one oscillation. Hence, the clock loses time.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments