As "T=2\\pi\\sqrt{\\frac{l}{g}}"
This is the time taken by the pendulum for one oscillation.
If temperature increases by "10\u00b0C" , then new length of pendulum "l'=l(1+\\alpha\u2206T)"
Length of the pendulum increases so
"T'=2\\pi\\sqrt{\\frac{l'}{g}}"
As "l'>l\\implies T'>T"
So the pendulum takes more time for one oscillation. Hence, the clock loses time.
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