Question

A charge experiences a force of 4.3 x 10 -6 N in a uniform electric field of intensity 7.0 N/C. What is the charge?

Answer 1

electric field intensity

$$E=\frac{F}{q}$$

then

$$q=\frac{F}{E}=\frac{4.3\cdot10^{-6}}{7.0}=0.6\cdot10^{-6} (C)$$