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Question #109564
A capacitor has a total charge of 6 μC stored. If it were possible to transfer this charge uniformly through a light with a current of 100 mA, how long would the light stay lit?
Expert's answer
We know that the charge is current times time:
Q
=
I
t
,
t
=
Q
I
=
6
⋅
1
0
−
6
100
⋅
1
0
−
3
=
6
⋅
1
0
−
5
s
.
Q=It,\\ \space\\ t=\frac{Q}{I}=\frac{6\cdot10^{-6}}{100\cdot10^{-3}}=6\cdot10^{-5}\text{ s}.
Q
=
I
t
,
t
=
I
Q
=
100
⋅
1
0
−
3
6
⋅
1
0
−
6
=
6
⋅
1
0
−
5
s
.
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on Jan 2024
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