What is the magnitude of the electric field at the point midway between them?
E+=kqr2=9⋅109⋅3⋅10−60.12=2700kV/mE_+=k\frac{q}{r^2}=9\cdot10^9\cdot \frac{3\cdot10^{-6}}{0.1^2}=2700kV/mE+=kr2q=9⋅109⋅0.123⋅10−6=2700kV/m
E−=kqr2=9⋅109⋅−7⋅10−60.12=6300kV/mE_-=k\frac{q}{r^2}=9\cdot10^9\cdot \frac{-7\cdot10^{-6}}{0.1^2}=6300kV/mE−=kr2q=9⋅109⋅0.12−7⋅10−6=6300kV/m
EΣ=E++E−=2700+6300=9000kV/mE_\Sigma=E_++E_-=2700+6300=9000kV/mEΣ=E++E−=2700+6300=9000kV/m Answer.
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