The flux
"\\Phi=B\\cdot A\\cdot\\cos\\alpha=B\\cdot\\pi R^2\\cdot\\cos\\alpha=0.0065\\cdot3.14\\cdot0.12^2\\cdot\\cos0\u00b0=0.3mWb" .
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addition to the question. calculate the flux where the normal vector to the surface of the ring is: i+j/√2
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Dear visitor, please use panel for submitting new questions
addition to the question. calculate the flux where the normal vector to the surface of the ring is: i+j/√2
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