Question #109299
A circular ring with a radius of 12.00 cm is in a uniform magnetic field of 6.50 x 103 Tesla which points in the positive y direction. calculate the flux where the normal vector to the surface of the ring is:
1
Expert's answer
2020-04-13T10:21:43-0400

The flux


Φ=B⋅A⋅cos⁡α=B⋅πR2⋅cos⁡α=0.0065⋅3.14⋅0.122⋅cos⁡0°=0.3mWb\Phi=B\cdot A\cdot\cos\alpha=B\cdot\pi R^2\cdot\cos\alpha=0.0065\cdot3.14\cdot0.12^2\cdot\cos0°=0.3mWb .


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Comments

Assignment Expert
13.04.20, 17:22

Dear visitor, please use panel for submitting new questions

veer
12.04.20, 18:25

addition to the question. calculate the flux where the normal vector to the surface of the ring is: i+j/√2

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