Answer to Question #106664 in Electricity and Magnetism for Baby Jane

Question #106664
An emf induced by rotating a 1000 turns, 20.0 cm diameter coil in the earth's 5.00×10^-5 T magnetic field. What average emf induced, given the plane of coil is originally perpendicular to the earth's field and is rotated to be parallel to the field in 10.0 ms
1
Expert's answer
2020-03-27T10:52:17-0400

The Faraday's law of electromagnetic induction says


emf=ΔΦΔt.{\rm emf}=-\frac{\Delta\Phi}{\Delta t}.

The change of magnetic field


ΔΦ=NBA(cos90cos0)\Delta\Phi=NBA(\cos 90^{\circ}-\cos 0^{\circ})=NBA=πr2NB=-NBA=-\pi r^2NB=π×(0.1)2×103×5×105=1.6×103Wb=-\pi\times (0.1)^2\times 10^3\times 5\times 10^{-5}=-1.6\times 10^{-3}\rm Wb

Hence

emf=1.6×10310×103=0.16V.{\rm emf}=\frac{1.6\times 10^{-3}}{10\times 10^{-3}}=0.16\:\rm V.


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Comments

Glimsriel
26.04.21, 15:05

Very clear answer... Thanks

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