As per the given question,
Amplitude(A)= 2cm
Wavelength (λ)(\lambda)(λ) =10cm
Frequency (f)=400Hz
We know that general equation of wave
y=Asin(ωt+ϕ)y=A\sin(\omega t+\phi)y=Asin(ωt+ϕ)
⇒ω=2πf=2π×400=800π\Rightarrow \omega = 2\pi f=2\pi \times 400=800\pi⇒ω=2πf=2π×400=800π
Phase angle ϕ=0\phi=0ϕ=0
Now, substituting the values
y=2sin(800πt+0)y=2 \sin(800\pi t+0)y=2sin(800πt+0)
⇒y=2sin(800πt)\Rightarrow y= 2\sin (800 \pi t)⇒y=2sin(800πt)
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