As per the given question,
Amplitude(A)= 2cm
Wavelength "(\\lambda)" =10cm
Frequency (f)=400Hz
We know that general equation of wave
"y=A\\sin(\\omega t+\\phi)"
"\\Rightarrow \\omega = 2\\pi f=2\\pi \\times 400=800\\pi"
Phase angle "\\phi=0"
Now, substituting the values
"y=2 \\sin(800\\pi t+0)"
"\\Rightarrow y= 2\\sin (800 \\pi t)"
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