Distance traveled by the wave P
"d=v_pt" ..............(1)
Distance traveled by the wave S
"d=v_s(t+17.3)" ...............(2)
equating eq1 and eq 2
"v_pt=v_s(t+17.3)\\\\t=\\dfrac{17.3v_s}{v_p-v_s}"
Substituting the value of t in the Eq 1 we will get he value of d
"d=\\dfrac{17.3v_pv_s}{v_p-v_s}=\\dfrac{17.3\\times7.8\\times4.5}{7.8-4.5}=\\dfrac{607.23}{3.5}=173.5m"
Comments
Leave a comment