ω=110 rad/s, λ=1.80 m\omega =110 \ rad/s,\; \lambda =1.80 \ mω=110 rad/s,λ=1.80 m
k,v − ?k, v \ - \ ?k,v − ?
Solution:
Angular wave number: k=2πλk=\frac{2\pi}{\lambda}k=λ2π
k=2π1.80=3.49 m−1k=\frac{2\pi}{1.80}=3.49 \ m^{-1}k=1.802π=3.49 m−1
Speed of the wave: v=ωkv=\frac{\omega}{k}v=kω
v=1103.49=31.51 m/sv=\frac{110}{3.49}=31.51\ m/sv=3.49110=31.51 m/s
Answer: k=3.49 m−1, v=31.51 m/s.k=3.49 \ m^{-1},\; v=31.51 \ m/s.k=3.49 m−1,v=31.51 m/s.
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