Question

What rate of change of current in a solenoid having self-inductance 19.4 mH
produces a self-induced emf of 100 mV in it?

Answer 1

$E_s=-L\frac{dI}{dt}$

$\lvert\frac{dI}{dt}\rvert=\frac{E_s}{L}=\frac{0.1}{0.0194}=5.15A/s$ Answer