Question

It takes 7.3 mJ to move a charge of 4.7 μC from Point A to Point C in an electric field. What is the potential difference between the two points?

Answer 1

The work done by an electric field

$$W=qV.$$

Hence, the potential difference

$$V=\frac{W}{q}=\frac{7.3\times 10^{-3}}{4.7\times 10^{-6}}=1553\:\rm V.$$