Question #103392

An electron experiences a force of 8.7 x 10 -12 N. What is the intensity of the electric field?

Expert's answer


A force acts on an electron in an electric field

F=e⋅EF=e \cdot E

Where will we write

E=Fe=8.7⋅10−121.6⋅10−19=5.438⋅107V/mE=\frac{F}{e}=\frac{8.7 \cdot 10^{-12}}{1.6 \cdot 10^{-19}}=5.438\cdot10^{7}V/m


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