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Answer to Question #103391 in Electricity and Magnetism for ddd

Question #103391
A positive charge of 2.8 mC experiences a 4.8 x 10 -2 N force when placed in a uniform electric field. What is the magnitude of the electric field?
1
Expert's answer
2020-02-26T10:20:25-0500

The magnitude of electric field is

"E=F\/q=4.8*10^{-2} N\/2.8*10^{-3} C=17.1 N\/C"


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