Answer to Question #103390 in Electricity and Magnetism for bjbnl

Question #103390
A positive charge of 6.6 µC and a negative charge of 4.0 µC exert a force of -25.0 N on each other. How far apart are the charges?
1
Expert's answer
2020-02-24T10:47:11-0500

F21=F12\vec{F_{21}}=-\vec{F_{12}}

F21=F12=F|\vec{F_{21}}|=|\vec{F_{12}}|=F

Behind Coulomb's Law

F=kq1q2r2F=k \cdot \frac{|q_1|\cdot |q_2|}{r^2}

Where will we write

r=kq1q2Fr=\sqrt{ \frac{k \cdot |q_1|\cdot |q_2|}{F}}

r=91096.61064.010625=0.097m=9.7smr=\sqrt{ \frac{9 \cdot10^9 \cdot 6.6 \cdot 10^{-6}\cdot 4.0 \cdot 10^{-6}}{25}}=0.097 m=9.7 sm



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