Question

Two electrons are separated by a distance of 1.60 m. What is the magnitude of the electric force between them?

Answer 1

Electric charge of electron is:

$q = 1.602 * 10^{-19}C$

$r = 1.6 m$

$k = 9 * 10^9$

The magnitude of the electric force is:

$F = k * \frac{q*q}{r^2}$

$F = 9*10^9*\frac{1.602*10^{-19}*1.602*10^{-19}}{1.6^2}=9.023*10^{-29}N$

Answer: $9.023*10^{-29}N$