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Question #102694
Two capacitors are connected in series c1=1f , v1=10v and c2=3f , v2= 20f find total voltage of the system 30 is not the answer

Expert's answer
Two capacitors are connected in series:
q
1
=
C
1
V
1
=
(
1
)
(
10
)
=
10
C
q_1=C_1V_1=(1)(10)=10\ C
q
1
=
C
1
V
1
=
(
1
)
(
10
)
=
10
C
q
2
=
C
2
V
2
=
(
3
)
(
20
)
=
60
C
q_2=C_2V_2=(3)(20)=60\ C
q
2
=
C
2
V
2
=
(
3
)
(
20
)
=
60
C
Total charge:
q
=
q
1
+
q
2
=
10
+
60
=
70
C
q=q_1+q_2=10+60=70\ C
q
=
q
1
+
q
2
=
10
+
60
=
70
C
Capacitance:
C
=
C
1
C
2
C
1
+
C
2
=
(
1
)
(
3
)
1
+
3
=
0.75
F
C=\frac{C_1C_2}{C_1+C_2}=\frac{(1)(3)}{1+3}=0.75\ F
C
=
C
1
+
C
2
C
1
C
2
=
1
+
3
(
1
)
(
3
)
=
0.75
F
Total voltage of the system:
U
=
q
C
=
70
0.75
=
93.3
V
U=\frac{q}{C}=\frac{70}{0.75}=93. 3\ V
U
=
C
q
=
0.75
70
=
93.3
V
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on Dec 2023
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