Two capacitors are connected in series:
"q_1=C_1V_1=(1)(10)=10\\ C""q_2=C_2V_2=(3)(20)=60\\ C"Total charge:
"q=q_1+q_2=10+60=70\\ C" Capacitance:
"C=\\frac{C_1C_2}{C_1+C_2}=\\frac{(1)(3)}{1+3}=0.75\\ F" Total voltage of the system:
"U=\\frac{q}{C}=\\frac{70}{0.75}=93.\n3\\ V"
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