Question

The length of a 500 turn solenoid is 3 cm . Calculate the magnitude at the center of magnetic field of the solenoid when it carries a 0.6 A current.

Answer 1

The formula of the magnetic field inside the solenoid is $B=\mu IN/l$

where μ: permeability

B: magnetic field

I: current intensity flowing in the cable

N: number of turns of the wire

L: Length of the solenoid

$B=4\pi*10^{-7}*0.6*500/0.03$

$B=1.26*10^{-2}T$