Question

Calculate the current flowing in resistor R1 (in mA) and calculate the power dissipated in the resistor. When voltage = 25V and Resistance=560 Ohms

Answer 1

$Voltage=25\ V$

$Resistance=560 \ ohm$

$Current,I=\frac{V}{R}=\frac{25}{560}=0.04464\ A=44.64\ mA$

$Power\ dissipitated=I^2R=0.04464^2\times560=1.116\ W$