Question

Calculate the current flowing in resistor R1 (in mA) and calculate the power dissipated in the resistor. When voltage = 25V and Resistance=560 Ohms

Answer 1

$Current, I =\frac{V}{R}=\frac{25}{560}=0.04464\ A=44.64\ mA$

$power\ dissipated=I^2R=0.04464^2\times 560=1.116\ W$