Question

how much energy is transferred by battery of end 4.5V and 1.0C of charge passes through it

Answer 1

The potential difference is equal to the work per unit charge

That is to say: $V=\frac{E}{Q}$

Where

• Potential difference. $V=4.5V$
• Energy $E=??$
• Electric charge $Q=1.0C$

Expression for energy

$E=Q*V$

Numerically evaluating

$E=1.0C*4.5V=4.5J$

The transferred energy is $\boxed{E=4.5J} \text[ j=joule]$