Charge is given by
where III is the current and ttt is the time.
Given I=5.0 A and t=2.00hrs=7200 sI=5.0\ A\ and \ t=2.00 hrs = 7200\ sI=5.0 A and t=2.00hrs=7200 s
Thus the charge flowing through the headlamp is 1.44×104 C1.44\times 10^4\ C1.44×104 C
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