2)For magnitude of electric field we have formula
"E=k\\frac{q}{r^2}"where
"k=9\\cdot 10^9"then
"E_1=9\\cdot 10^9 \\cdot \\frac{1\\cdot 10^{-6}}{0.25}=36(kV\/m)""E_2=9\\cdot 10^9 \\cdot \\frac{3\\cdot 10^{-6}}{0.25}=108(kV\/m)"
3)resultant field
"\\vec{E}=\\vec{E_1}+\\vec{E_3}""E=E_3-E_1""E=72(kV\/m)"4)Potential in dot (0,0)
"P_1=\\frac{kq_3}{1}-\\frac{kq_2}{0.5}=-9(kV)"Work is
"A=q_1(P_1-P(infinity))""E=10^{-6}\\cdot (9000-0)=9(mJ)"
5)Total potential in point P
"P_p=\\frac{kq_1}{0.5}+\\frac{kq_3}{0.5}=72(kV)"
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Your service is so helpful, blessings
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